# Write a program to find the value of y for a particular value of n. The a, x, b, n is input by user if n=1 y=ax%b if n=2 y=ax2+b2 if n=3 y=a-bx if n=4 y=a+x/b

__ Code:-__

#include<stdio.h>

#include<math.h>

int main()

{

int a,x,b,n,y;

printf(“Enter the value of a,x,b,nn”);

scanf(“%d%d%d%d”,&a,&x,&b,&n);

if(n==1)

y=(a*x)%b;

if(n==2)

y=(a*x*x)+(b*b);

if(n==3)

y=a–b*x;

if(n==4)

y=a+(x/b);

printf(“Value of the y is: %d”,y);

return 0;

}

__Output:-__

Enter the value of a,x,b,n

2 3 41 1

Value of the y is : 6

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