Write a program to find the value of y for a particular value of n. The a, x, b, n is input by user if n=1 y=ax%b if n=2 y=ax2+b2 if n=3 y=a-bx if n=4 y=a+x/b
Code:-
#include<stdio.h>
#include<math.h>
int main()
{
int a,x,b,n,y;
printf(“Enter the value of a,x,b,nn”);
scanf(“%d%d%d%d”,&a,&x,&b,&n);
if(n==1)
y=(a*x)%b;
if(n==2)
y=(a*x*x)+(b*b);
if(n==3)
y=a–b*x;
if(n==4)
y=a+(x/b);
printf(“Value of the y is: %d”,y);
return 0;
}
Output:-
Enter the value of a,x,b,n
2 3 41 1
Value of the y is : 6
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