Program to check whether a number is Armstrong or not. -

What is armstrong number:- Click here

Code:-

#include<stdio.h>
#include<conio.h>
int main()
{
 int n,n1,n2,r,s=1,sum=0; //r=reminder
 printf(“Enter a number”);
 scanf(“%d”,&n);
 n1=n;
 n2=n;
 while(n!=0)
 {
 r=n%10;
 n=n/10;
 while(n1!=0)
 {
 s=s*r;
 n1=n1/10;
 }
 sum=sum+s;
 s=1;
 n1=n2;
 }
 if(sum==n2)
 printf(“number is Armstrong”);
 else
 printf(“number is not Armstrong”);
 return 0;
}

Output:-

Enter a number
153
number is Armstrong

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