Program to check that number is perfect square or not
Program to check that number is perfect square or not : –
Method 1:- 1. find the square root of the number .
2. multiple the square root two times .
3. check (sq*sq)==number then it is perfect square
4. otherwise not a perfect square
Code in C++:-
#include<bits/stdc++.h> using namespace std; int main() { int n; cout<<"Enter a number\n"; cin>>n; // checking for perfect square long long sq=sqrt(n); if(sq*sq==n) cout<<n<<" is a perfect square"<<endl; else cout<<n<<" is not a perfect square"<<endl; return 0; }
Output:-
Enter a number 6 6 is not a perfect square
Method 2: –
- in this method we will use the ceil and floor .
- if ceil(sqrt (n))==floor(sqrt(n)) then number is perfect square.
Code in C++:-
#include<bits/stdc++.h> using namespace std; int main() { int n; cout<<"Enter a number\n"; cin>>n; // checking for perfect square double sq=sqrt(n); cout<<sq<<endl; if(ceil(sq)==floor(sq)) cout<<n<<" is a perfect square"<<endl; else cout<<n<<" is not a perfect square"<<endl; return 0; }
python code:-
import math n=int(input()) x=int(math.sqrt(n)) if (x*x)==n: print(n,"is a perfect square") else: print(n,"is not a perfect square")
output:-
49 49 is a perfect square
Program to check that number is perfect square or not
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