Program to check that number is perfect square or not

Program to check that number is perfect square or not : –

Method 1:-   1. find the square root of the number .

2. multiple the square root two times .

3. check (sq*sq)==number then it is perfect square

4. otherwise not a perfect square

Code  in C++:-

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int n;
    cout<<"Enter a number\n";
    cin>>n;
    
    // checking for perfect square
    long long sq=sqrt(n);
    if(sq*sq==n)
      cout<<n<<" is a perfect square"<<endl;
    else
      cout<<n<<" is not a perfect square"<<endl;
     return 0;
}

Output:- 

Enter a number
6
6 is not a perfect square

Method 2: –

• in this method we will use the ceil and floor .
• if ceil(sqrt (n))==floor(sqrt(n)) then number is perfect square.

Code in C++:-

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int n;
    cout<<"Enter a number\n";
    cin>>n;
    
    // checking for perfect square
    double sq=sqrt(n);
    cout<<sq<<endl;
    if(ceil(sq)==floor(sq))
      cout<<n<<" is a perfect square"<<endl;
    else
      cout<<n<<" is not a perfect square"<<endl;
     return 0;
}

python code:-

import math
n=int(input())
x=int(math.sqrt(n))
if (x*x)==n:
    print(n,"is a perfect square")
else:
    print(n,"is not a perfect square")

output:-

49
49 is a perfect square

 

Program to check that number is perfect square or not

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