# Multiple choice questions on chi-square distribution( statistical techniques-III) for AKTU Examination

Here In this post we will discuss the important questions of the Sample distribution of statistical techniques-III . These questions will help you in your mid semesters exams or the semester exams or any other competitive exams. And this will also help in your upcoming AKTU semester exam.

*****************************************************************************

1. Consider a set of 18 samples from a standard normal distribution. We square each sample and sum all the squares. The number of degrees of freedom for a Chi Square distribution will be?

a) 17

b) 18

c) 19

d) 20

Answer: b

Explanation: In Chi Square Distribution the number of standard normal derivatives or samples equals the number of degrees of freedom.

Here total number of standard normal derivatives = 18.

Hence the number of degrees of freedom for a Chi Square distribution = 18.

advertisement

2. What is the mean of a Chi Square distribution with 6 degrees of freedom?

a) 4

b) 12

c) 6

d) 8

Answer: c

Explanation: By the property of Chi Square distribution, the mean corresponds to the number of degrees of freedom.

Degrees of freedom = 6.

Hence mean = 6.

3. Which Chi Square distribution looks the most like a normal distribution?

a) A Chi Square distribution with 4 degrees of freedom

b) A Chi Square distribution with 5 degrees of freedom

c) A Chi Square distribution with 6 degrees of freedom

d) A Chi Square distribution with 16 degrees of freedom

Answer: c

Explanation: When the number of degrees of freedom in Chi Square distribution increases it tends to correspond to normal distribution. The option with a maximum number of degrees of freedom is 16.

4. A bag contains 80 chocolates. This bag has 4 different colors of chocolates in it. If all four colors of chocolates were equally likely to be put in the bag, what would be the expected number of chocolates of each color?

a) 12

b) 11

c) 20

d) 9

Answer: c

Explanation: If all four colors were equally likely to be put in the bag, then the expected frequency for a given color would be 1/4th of the chocolates.

N = 80, r = 1/4

So, the expected frequency = N*r = (1/4)*(80) = 20.

5. The Variance of Chi Squared distribution is given as k.

a) True

b) False

Answer: b

Explanation: The Mean of Chi Squared distribution is given as k. The Variance of Chi Squared distribution is given as 2k.

6. Which of these distributions is used for a testing hypothesis?

a) Normal Distribution

b) Chi-Squared Distribution

c) Gamma Distribution

d) Poisson Distribution

Answer: b

Explanation: Chi-Squared Distribution is used for testing hypothesis. The value of X2 decides whether the hypothesis is accepted or not.

__Recommended post:-__

__Hackerearth Problems:-__

- Very Cool numbers | Hacker earth solution
- Birthday party | Hacker earth solution
- Most frequent | hacker earth problem solution
- program to find symetric difference of two sets
- cost of balloons | Hacker earth problem solution
- Chacha o chacha | hacker earth problem solution
- jadu and dna | hacker earth solution
- Bricks game | hacker earth problem
- Anti-Palindrome strings | hacker earth solution
- connected components in the graph | hacker earth data structure
- odd one out || hacker earth problem solution
- Minimum addition | Hackerearth Practice problem
- The magical mountain | Hackerearth Practice problem
- The first overtake | Hackerearth Practice problem

__
__

__Hackerrank Problems:-__- Playing With Characters | Hackerrank practice problem solution
- Sum and Difference of Two Numbers | hackerrank practice problem solution
- Functions in C | hackerrank practice problem solution
- Pointers in C | hackerrank practice problem solution
- Conditional Statements in C | Hackerrank practice problem solution
- For Loop in C | hackerrank practice problem solution

__Data structure:-__

- Program to find cycle in the graph
- Implementation of singly link list
- Implementation of queue by using link list
- Algorithm of quick sort
- stack by using link list
- program to find preorder post order and inorder of the binary search tree
- Minimum weight of spanning tree
- Preorder, inorder and post order traversal of the tree

__Key points:-__