Matrix sum | Infytq solution
Matrix sum | Infytq solution
Problem:- Given a row/column count and a matrix, your job is to find those possible 2*2 matrix where each should follow the given rule :
-> Each element of matrix should be divisible by sum of its digits.
Input :
First Input : Row count, Column Count
Second Input : Matrix
Output :
2*2 matrices satisfying the rule.
Sample Testcases :
I/P 1:
4 3
40 42 2
30 24 27
180 190 40
11 121 13
O/P 1:
40 42
30 24
30 24
180 190
24 27
190 40
Code:-
r, c = list(map(int, input().split())) mat = [] for i in range(r): l = list(map(int, input().split())) mat.append(l) for i in range(r - 1): s = 0 for j in range(c - 1): n = mat[i][j] s = 0 while (n != 0): s += (n % 10) n //= 10 if (mat[i][j] % s != 0): break n = mat[i + 1][j] s = 0 while (n != 0): s += (n % 10) n //= 10 if (mat[i + 1][j] % s != 0): break n = mat[i][j + 1] s = 0 while (n != 0): s += (n % 10) n //= 10 if (mat[i][j + 1] % s != 0): break n = mat[i + 1][j + 1] s = 0 while (n != 0): s += (n % 10) n //= 10 if (mat[i + 1][j + 1] % s != 0): break print(mat[i][j], mat[i][j + 1]) print(mat[i + 1][j], mat[i + 1][j + 1])
Matrix sum | Infytq solution
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