# Matrix sum | Infytq solution

# Matrix sum | Infytq solution

** Problem:- ** Given a row/column count and a matrix, your job is to find those possible 2*2 matrix where each should follow the given rule :

-> Each element of matrix should be divisible by sum of its digits.

**Input : **

First Input : Row count, Column Count

Second Input : Matrix

**Output : **

2*2 matrices satisfying the rule.

Sample Testcases :

**I/P 1:**

4 3

40 42 2

30 24 27

180 190 40

11 121 13

**O/P 1:**

40 42

30 24

30 24

180 190

24 27

190 40

**Code:-**

r, c = list(map(int, input().split())) mat = [] for i in range(r): l = list(map(int, input().split())) mat.append(l) for i in range(r - 1): s = 0 for j in range(c - 1): n = mat[i][j] s = 0 while (n != 0): s += (n % 10) n //= 10 if (mat[i][j] % s != 0): break n = mat[i + 1][j] s = 0 while (n != 0): s += (n % 10) n //= 10 if (mat[i + 1][j] % s != 0): break n = mat[i][j + 1] s = 0 while (n != 0): s += (n % 10) n //= 10 if (mat[i][j + 1] % s != 0): break n = mat[i + 1][j + 1] s = 0 while (n != 0): s += (n % 10) n //= 10 if (mat[i + 1][j + 1] % s != 0): break print(mat[i][j], mat[i][j + 1]) print(mat[i + 1][j], mat[i + 1][j + 1])

Matrix sum | Infytq solution

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