Program to delete duplicates from a link list

Lucky Four | Codechef solution

Problem ( Lucky Four | Codechef solution ):-

Read problems statements in Mandarin Chinese and Russian.

Kostya likes the number 4 much. Of course! This number has such a lot of properties, like:

  • Four is the smallest composite number;
  • It is also the smallest Smith number;
  • The smallest non-cyclic group has four elements;
  • Four is the maximal degree of the equation that can be solved in radicals;
  • There is four-color theorem that states that any map can be colored in no more than four colors in such a way that no two adjacent regions are colored in the same color;
  • Lagrange’s four-square theorem states that every positive integer can be written as the sum of at most four square numbers;
  • Four is the maximum number of dimensions of a real division algebra;
  • In bases 6 and 12, 4 is a 1-automorphic number;
  • And there are a lot more cool stuff about this number!

Impressed by the power of this number, Kostya has begun to look for occurrences of four anywhere. He has a list of T integers, for each of them he wants to calculate the number of occurrences of the digit 4 in the decimal representation. He is too busy now, so please help him.

Input of Lucky Four | Codechef solution

The first line of input consists of a single integer T, denoting the number of integers in Kostya’s list.

Then, there are T lines, each of them contain a single integer from the list.

Output

Output T lines. Each of these lines should contain the number of occurences of the digit 4 in the respective integer from Kostya’s list.

Constraints

  • 1 ≤ T ≤ 105
  • (Subtask 1): 0 ≤ Numbers from the list ≤ 9 – 33 points.
  • (Subtask 2): 0 ≤ Numbers from the list ≤ 109 – 67 points.

Sample Input 1

5
447474
228
6664
40
81

Sample Output 1

4
0
1
1
0

 

Code:-

#include <iostream>
using namespace std;

int main() {
    int  t,n;
    cin>>t;
    while(t--)
    {
        int count=0;
        cin>>n;
        while(n!=0)
        {
            int r=n%10;
            if(r==4)
              count++;
            n=n/10;
        }
        cout<<count<<endl;
    }
    return 0;
}

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