Program to delete duplicates from a link list

List of the Depth | Solution of cracking the coding interview

 Program (List of the Depth | Solution of cracking the coding interview):-

                    Given the binary tree , design the an algorithm which creates a linked list of all the nodes at each depth (e.g. if you have a tree with depth D, you’ll have D linked lists).

Code (List of the Depth | Solution of cracking the coding interview):-

#include<bits/stdc++.h>
using namespace std;

vector<int> arr[50];
struct node 
{
    int data;
    node * left ,*right;
};
struct node * root;

node* CreateNode()
{
    struct node * temp;
    temp=new node;
    return temp;
}

void BinarySearchTree(int a)
{
    node * temp,*t;
    temp=CreateNode();
    temp->data=a;
    temp->left=NULL;
    temp->right=NULL;
    if(root==NULL)
      root=temp;
    else
    {
        t=root;
        while(t!=NULL)
        {
            if(t->data>a)
            {
                if(t->left==NULL)
                {
                    t->left=temp;
                    t=t->left;
                }
                t=t->left;
            }
            else
            {
                if(t->right==NULL)
                {
                    t->right=temp;
                    t=t->right;
                }
                t=t->right;
                
            }
            
        }
    }
}

void preorder(node *t)
{
    if(t)
    {
        cout<<t->data<<" ";
        preorder(t->left);
        preorder(t->right);
    }
}
int main()
{
    int n;
    cout<<"Enter the number of nodes"<<endl;\
    cin>>n;
    int a;
    cout<<"Enter the values"<<endl;
    for(int i=0;i<n;i++)
    {
        cin>>a;
        BinarySearchTree(a);
    }
    preorder(root);
    return 0;
    
}

 

Output:-

Enter the number of nodes
10
Enter the values
1 12 11 13 23 43 10 9 67 4
1 12 11 10 9 4 13 23 43 67

 

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