List of the Depth | Solution of cracking the coding interview
Program (List of the Depth | Solution of cracking the coding interview):-
Given the binary tree , design the an algorithm which creates a linked list of all the nodes at each depth (e.g. if you have a tree with depth D, you’ll have D linked lists).
Code (List of the Depth | Solution of cracking the coding interview):-
#include<bits/stdc++.h> using namespace std; vector<int> arr[50]; struct node { int data; node * left ,*right; }; struct node * root; node* CreateNode() { struct node * temp; temp=new node; return temp; } void BinarySearchTree(int a) { node * temp,*t; temp=CreateNode(); temp->data=a; temp->left=NULL; temp->right=NULL; if(root==NULL) root=temp; else { t=root; while(t!=NULL) { if(t->data>a) { if(t->left==NULL) { t->left=temp; t=t->left; } t=t->left; } else { if(t->right==NULL) { t->right=temp; t=t->right; } t=t->right; } } } } void preorder(node *t) { if(t) { cout<<t->data<<" "; preorder(t->left); preorder(t->right); } } int main() { int n; cout<<"Enter the number of nodes"<<endl;\ cin>>n; int a; cout<<"Enter the values"<<endl; for(int i=0;i<n;i++) { cin>>a; BinarySearchTree(a); } preorder(root); return 0; }
Output:-
Enter the number of nodes 10 Enter the values 1 12 11 13 23 43 10 9 67 4 1 12 11 10 9 4 13 23 43 67
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