Birthday Party
Problem:-
Mr. X’s birthday is in next month. This time he is planning to invite N of his friends. He wants to distribute some chocolates to all of his friends after party. He went to a shop to buy a packet of chocolates.
At chocolate shop, each packet is having different number of chocolates. He wants to buy such a packet which contains number of chocolates, which can be distributed equally among all of his friends.
Help Mr. X to buy such a packet.
Input:
First line contains T, number of test cases.
Each test case contains two integers, N and M. where is N is number of friends and M is number number of chocolates in a packet.
Output:
In each test case output “Yes” if he can buy that packet and “No” if he can’t buy that packet.
Constraints:
1<=T<=20
1<=N<=100
1<=M<=10^5
Problem Setter:
Akash Rakshit
At chocolate shop, each packet is having different number of chocolates. He wants to buy such a packet which contains number of chocolates, which can be distributed equally among all of his friends.
Help Mr. X to buy such a packet.
Input:
First line contains T, number of test cases.
Each test case contains two integers, N and M. where is N is number of friends and M is number number of chocolates in a packet.
Output:
In each test case output “Yes” if he can buy that packet and “No” if he can’t buy that packet.
Constraints:
1<=T<=20
1<=N<=100
1<=M<=10^5
Problem Setter:
Akash Rakshit
Explanation
Test Case 1:
There is no way such that he can distribute 14 chocolates among 5 friends equally.
Test Case 2:
There are 21 chocolates and 3 friends, so he can distribute chocolates eqally. Each friend will get 7 chocolates.
There is no way such that he can distribute 14 chocolates among 5 friends equally.
Test Case 2:
There are 21 chocolates and 3 friends, so he can distribute chocolates eqally. Each friend will get 7 chocolates.
Time Limit:1.0 sec(s) for each input file.
Memory Limit:256 MB
Source Limit:1024 KB
solution:-
#include<stdio.h>
int main()
{
int t,n,i;
long int m;
scanf(“%d”,&t);
for(i=1;i<=t;i++)
{
scanf(“%d”,&n);
scanf(“%ld”,&m);
if(m%n==0)
printf(“Yesn”);
else
printf(“Non”);
}
return 0;
}
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